[BC] trouble with an old BC-1G need advice

[Jerry Mathis]

He was reading a meter wrong. PA Volts, not output power. Silly 
mistake, I've done that, I'm sure we all have  :)

Jerry Mathis


On 4/2/08, 
<mailto:RichardBJohnson at comcast.net>RichardBJohnson at comcast.net 
<<mailto:RichardBJohnson at comcast.net>RichardBJohnson at comcast.net> wrote:
I'm assuming this is not an April Fools joke.

Ammeter reading =  square root of [power you want divided by the resistance]

I = sqrt(P/R)

If you want 1250 watts and the line impedance is 50 ohms it's:
I = sqrt(1250/50)
I = sqrt(25)
i = 5 amperes