[BC] trouble with an old BC-1G need advice

[RichardBJohnson at comcast.net]

I'm assuming this is not an April Fools joke.

Ammeter reading =  square root of [power you want divided by the resistance]

I = sqrt(P/R)

If you want 1250 watts and the line impedance is 50 ohms it's:
I = sqrt(1250/50)
I = sqrt(25)
i = 5 amperes

Maybe you want 1000 watts exactly. It's:
I = sqrt(1000/50)
I =  sqrt(20)
I = 4.47 amperes

Use this math as a simple prototype to substitute your numbers.
It works for the tower as well. Let's pretend that the tower impedance
was 31 + j16. Ignore the "j stuff, that's reactance.

Let's say you want the maximum power allowed there, and it is
1000 watts. Then:

I = sqrt(1000 / 31)
I = sqrt(32.258)
I = 5.68 amperes

--
Cheers,
Richard B. Johnson
Read about my book
http://www.LymanSchool.org


 -------------- Original message ----------------------
From: BOYDSIRBOYD at aol.com
> as per the owner it has always been that way,, there are two other  engineers 
>  
> who have worked on this thing in the past and they all say  the same thing. 
> i'm  
> now at a loss as to what needs to be done.
>  
> and CHUCK  is the best in the world and another engineer he had used  at one 
> time had worked for GATES and was the best on these transmitters. and the  
> readings all had to be the same as the normal readings to be right. or it didn't  
> work like it was suppose to. that's why i need advice and help.
>  
> bill