[BC] Total Power Of An AM Directional Array

[RichardBJohnson@comcast.net]

No. That's why there is a measured common-point impedance and why the power
is measured there. The currents at each of the towers are probably not in phase
with each other. That's why you can't just add the "tower powers" up. Also, the
impedance seen at a tower is the "effective" impedance which is modified by
the mutual coupling between the towers. The mutual coupling is not just
the transformed impedance because of proximity, but also the coupling that
results from power being fed to "your" tower from an adjacent tower.  This
power can even create "negative" towers where the observed current comes
from the tower back toward the common-point, rather than to the tower from
the common-point.
--
Cheers,
Richard B. Johnson
Read about my book
http://www.AbominableFirebug.com


  -------------- Original message ----------------------
From: Tom <mwam at box311.net>
 > In an AM multiple tower directional array, does the power of
 > all towers as determined by "P equals I squared times R" add
 > up to the authorized power of the station?
 >
 > For example, for a one thousand watt station with four towers
 > would the power of each tower add up to one thousand watts?
 >
 > Thanks to all who have answered my occasional questions to
 > satisfy my curiosity about radio, even if the questions
 > appear to be dumb ones.
 >



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