[BC] need a NON-technical explanation
Richard Fry
rfry at adams.net
Fri Nov 12 12:14:52 CST 2010
> However, LONG after the MKS system (and kHz) was adopted,
> mV/m/kW at 1 mile was retained by the FCC, etc
_____________
Although it is widely used, "mV/m/kW" for the IDF at some distance is not
scientifically accurate, IMO. It implies that the IDF is directly
proportional to power.
If the IDF was "306 mV/m/kW," this terminology might lead one to believe
that with 10 kW, the IDF would be 3,060 mV/m.
But IDF is not related directly to the change in power -- it is related to
the square root of that change. With 10 kW, the IDF in this example would
be 306 * SQRT(10) = 967.7 mV/m.
A more accurate form would be: mV/m at 1 km for X kW of applied power.
RF
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