[BC] need a NON-technical explanation

Richard Fry rfry at adams.net
Fri Nov 12 12:14:52 CST 2010


> However, LONG after the MKS system (and kHz) was adopted,
> mV/m/kW at 1 mile was retained by the FCC,  etc
_____________

Although it is widely used, "mV/m/kW" for the IDF at some distance is not 
scientifically accurate, IMO.  It implies that the IDF is directly 
proportional to power.

If the IDF was "306 mV/m/kW," this terminology might lead one to believe 
that with 10 kW, the IDF would be 3,060 mV/m.

But IDF is not related directly to the change in power -- it is related to 
the square root of that change.  With 10 kW, the IDF in this example would 
be 306 * SQRT(10) = 967.7 mV/m.

A more accurate form would be:  mV/m at 1 km for X kW of applied power.

RF



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